Question

For what values (cases) of the variables the expression does not exist:
`(3)/(4y+2)`

Answer 1

y = -
`(1)/(2)`

Explanation:

Given

`(3)/(4y+2)`

The denominator of the expression cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that y cannot be, that is

4y + 2 = 0 ( subtract 2 from both sides )

4y = - 2 ( divide both sides by 4 )

y =
`(-2)/(4)` = -
`(1)/(2)` ← excluded value