Question

A beaker has 0.2 M of Na2SO4. What will be the concentration of sodium and sulfate ions?

Answer 1

Na+-0.0648M

SO4²-0.1352M

Step-by-step explanation:

First find the R.A.M of the sodium sulphate

(23×2)+(32)+(16×4)=142

Find the portion of sodium ions=46/142×0.2

=0.0648M

Sulphate=

0.2-0.0648=0.1352M