Question

I need help with this one too

Answer 1

Step-by-step explanation: Is this what you needed ?

I Hope i am right

`x^2-3x+7\\y =x^2-3x+7\\x = -b / 2a\\x = -(-3)/2(1)\\x = 3/2\\y=(3/2)^2-3(3/2) +7\\y=9/4 -9/2 +7\\y = -9/4+7\\y =19/4`

`Sustitute -y=5x-9-into\\y=x^2-3x+7\\(5x-9)^2=x^2-3x+7\\Solve-for-x \\x =4\\substitute-4-for - -in ; y=5x-9\\y = 5(4)-9\\y = 20-9\\y =11`

Answer 2

Hey there! :)

Answer:

y = 11.

Explanation:

Set both of the equations equal:

5x - 9 = x² - 3x + 7

Rearrange the equation:

0 = x² - 3x - 5x + 9 + 7

Combine like terms:

0 = x² - 8x + 16

Factor:

0 = (x -4)²

Solve for x:

0 = x - 4

x = 4.

Plug this into an equation to solve for 'y':

y = 5(4) - 9

y = 20 - 9

y = 11.