Question

An arrow on a spinner is spun 250 times. Some of the results are shown below. The relative frequency of landing on a 4 is the same as the relative frequency of landing on a 5 Work out the relative frequency of landing on a 4

Answer 1

11/50

Explanation:

The frequency numbers for landing on 1, 2, and 3 are:

25, 53, 62.

We add them up to get: 25 + 53 + 62 = 140

Since 250 spins were made, and 140 of them landed on 1, 2, or 3, then

250 - 140 = 110,

so 110 landed on 4 or 5.

We are told the numbers of spins landing on 4 and 5 are equal, so

110/2 = 55,

so the spinner landed 55 times on 4 and 55 times on 5.

relative frequency = 55/250 = 11/50