Question

two cards are drawn without replacement from a standard deck of 52 playing cards. what is the probability of choosing a diamond and then without replacement another diamond? express your answer as a fraction or decimal number rounded to four decimal places.

Answer 1

1/17

Explanation:

There are 13 diamond cards in a standard 52-card deck.

First drawing:

13 diamonds

52 total cards

After the first drawing you already took a diamond, so there are 12 diamonds left out of 51 total cards.

p(diamond and diamond) = 13/52 * 12/51 = 1/4 * 4/17 = 1/17