Question

What is the equation of the line that passes through the point (-2,14) and is perpendicular to the line with the following equation?

y = -x-1
OA
y =
OB
y =
- + 9
o + 16
1 - 12
Oc.
y =
OD.
y =
+ 19

Answer 1

y = x + 16

Explanation:

Given the equation y = -x - 1, we see that the slope (the coefficient of the x term) is -1. A line perpendicular to this one has a slope which is the negative reciprocal of the given equation: +1.

Using the point-slope formula for the equation of a straight line, we get:

y - 14 = +1(x + 2), or y - 14 = x + 2, or y = x + 16

Answer 2

y = x + 16

Explanation:

Step 1: Find slope of perpendicular line

Take the negative reciprocal of the 1st line

m = 1

Step 2: Find b

y = x + b

14 = -2 + b

b = 16

Step 3: Write equation

y = x + 16