Answer: 7, 14, 21, 28
Explanation:
Let first multiple = x
So, second multiple = x + 7
Third = x + 14
Fourth = x + 21
According to the question,
=>x + (x + 7)+ (x + 14) + (x + 21) = 70
=>4x + 42 = 70
=>4x = 28
=>x = 7
So, the multiples are 7(x), 14(x+7), 21(x+14), 28(x+21)