Answer:
The time taken by the car to come at rest is 2.5 seconds
Step-by-step explanation:
The parameters given are;
Speed of bus = 72 km/hr
Distance at which bus stopped = 25 m
Given that the speed and the distance covered before stopping are j=known, we have;
v² = u² - 2·a·s
Where:
v = Final velocity = 0
a = Deceleration of the bus
s = Distance covered while decelerating = 23 m
u = Initial velocity = 72 km/hr = 20 m/s
Which gives;
0² = (20 m/s)² - 2×a×25 m
20² = 2×a×25 m
a = 20²/(2×25) = 8 m/s²
The time, t, it takes for the car to come at rest is given by the relation;
v = u - at
0 = 20 - 8×t
t = 20/8 = 2.5 s.