Question

I NEED HELP PLEASE, THANKS! :)

Answer 1

x = 124

Explanation:

`6 + \sqrt[5]{249 - 2x} = 7 \\ \sqrt[5]{249 - 2x} = 7 - 6 \\ \sqrt[5]{249 - 2x} = 1 \\ {\sqrt[5]{249 - 2x} }^(5) = {1}^(5)`

`249 - 2x = 1 \\ - 2x = 1 - 249 \\ - 2x = - 248 \\ ( - 2x)/( - 2) = ( - 248)/( - 2)`

`x = 124`

Answer 2

124

Explanation:

First subtract 6 to both sides.

`\sqrt[5]{249-2x} = 1`

Then take the 5th power of both sides to remove the radical.

`249-2x=1^5`

Which is essentially:

-2x = 1 - 249

-2x = -248

Divide both sides by -2

x = 124

And there ya go :)