Question

The sum of all digits in the numbers 44, 45 and 46 is 27 because (4+4)+(4+5)+(4+6)=27. Find the sum of digits in the first 25 counting numbers: 1, 2, 3, …, 25.

In other words....
1+2+3+4+5+6+7+8+9+1+0+1+1+1+2+1+3+1+4+1+5+1+6+1+7+1+8+1+9+2+0+2+1+2+2+2+3+2+4+2+5

Answer 1

The sum of all digits in the first 25 counting numbers is 127

Hope this helps