Question

Solve the system of equations and choose the correct ordered pair. 3y=4x+7 and 5y=4x+25​

Answer 1

Explanation:

3y=4x+7_equation 1

5y=4x+25_equation 2

multiply equation 1 by 5 an equation 2 by 3

15y=20x+35_equation 3

15y=12x+75_equation 4

subtract equations 4 from equation 3

0=8x-40

40=8x

divide both sides by 8

x=5

substitute x into equation 1

3y=4(5)+7

3y=20+7

3y=27

divide both sides by 3

y=9

Answer 2

(5,9)

Explanation:

3y=4x+7

5y=4x+25​

Subtract the two equations to eliminate x

5y=4x+25

-( ​3y=4x+7)

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2y = 0x +18

Divide by 2

2y/2 = 18/2

y =9

Now find x

3y = 4x+7

3*9 = 4x+7

27 = 4x+7

Subtract 7

20 = 4x

Divide 4

20/4 = 4x/4

5 =x

(5,9)