Question

Mr. Rifkin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left. How many digital cameras did he have at first?

Answer 1

therefore, he had 181 digital cameras at first

Explanation:

total=240

digital= 3x+82

manual= x+26

total= digital + manual

240= 3x+82+26+x

x= 240-108/4

x= 33

digital= 3×33+83

=181

Answer 2

181

Explanation:

Let d represent the number of digit cameras Mr. Rifkin had at first. Then 240-d is the number of manual cameras he had. The after-donation numbers are ...

(d -82) . . . digital cameras after donating 82

(240 -d) -26 . . . manual cameras after donating 26

These values are related by ...

(d -82) = 3((240 -d) -26)

4d = 724 . . . . . add 3d+82 and simplify

d = 181

Rifkin had 181 digital cameras at first.

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Check

Rifkin started with 181 digital cameras and 59 manual cameras. After donation, he had 99 digital cameras and 33 manual cameras, so 3 times as many digital as manual—as required.