Question

10 POINTS!!!!

suppose f(x)=x^2 -1 find the graph of f(2/3x)
please include a picture of the graph

Answer 1

Explanation:

`f( (2)/(3) x) = (4)/(9) {x}^(2) - 1 \\ (4)/(9) {x}^(2) - 1 = 0 \\ \sqrt{ {x}^(2) } = \sqrt{ (9)/(4) } \\ x = (3)/(2) \\ x = - (3)/(2)`

we have three points of the graph

(0,-1) min point

and those two values for x.

so: