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3k(x+2)+2 = 5x+8
How do I solve for k while keeping x smaller then 3?

1 Answer

3 votes

Answer:

k=(5x+6)/(3x+6) and k<3/5

Explanation:

  • 3k(x+2)+2 = 5x+8
  • 3k(x+2)=5x+6
  • 3k=(5x+6)/(x+2)
  • k=(5x+6)/(3x+6)

it is solved for k

and considering the condition for x<3:

  • 3k(x+2)+2 = 5x+8
  • 3kx+6k=5x+6
  • (5-3k)x=6k-6
  • x= (6k-6)/(5-3k)
  • x<3 ⇒ (6k-6)/(5-3k)<3 ⇒ 6k-6<15-9k ⇒ 15k<9 ⇒ k<9/15 ⇒ k<3/5

So,

k=(5x+6)/(3x+6) and k<3/5

User Hammao
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