Question

In the reaction 2Cu2O + Cu2S --> 6Cu + SO2

When 10.5 grams of Copper I oxide is reacted with unlimited Copper I sulfide how many grams of
Copper will be produced?
14.0 grams
2.73 grams
28.0 grams
O 16.9 grams
35.2 grams

Answer 1

14.0 g

Step-by-step explanation:

Step 1: Write the balanced equation

2 Cu₂O + Cu₂S ⇒ 6 Cu + SO₂

Step 2: Calculate the moles corresponding to 10.5 g of copper (I) oxide

The molar mass of Cu₂O is 143.09 g/mol.

`10.5g * (1mol)/(143.09g) = 0.0734 mol`

Step 3: Calculate the moles of copper produced from 0.0734 moles of copper (I) oxide

The molar ratio of Cu₂O to Cu is 2:6. The moles of Cu produced are 6/2 × 0.0734 mol = 0.220 mol

Step 4: Calculate the mass corresponding to 0.220 mol of copper

The molar mass of Cu is 63.55 g/mol.

`0.220mol * (63.55g)/(mol) = 14.0 g`