Answer:
12 and 30
Explanation:
a and b are the numbers
HCF(a,b)=6
LCM(a,b)=60
We know that ab=HCF(a,b)*LCM(a.b)
ab=6*60=360
both a and b must be greater than 6 and factor of 60
a=12 and b=360/12=30 is the solution
We just have to find 2 multiples of 6 that are factors of 60 as well. The factors of 60 (that are also multiples of 6 and greater than 6) are 12 and 30, so that is the answer.
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