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How many 2-digit numbers are among the terms of the arithmetic sequence 2, 7, 12, 17, ...?

1 Answer

3 votes

Answer:

20

Explanation:

It seems like the rule of this sequence is to add 5 (since 2 + 5 = 7 and 7 + 5 = 12). We already are given that we have 2 2-digit numbers (12 and 17) so let's see if there are any more. The sequence continues to 22, 27, 32, 37, 42, 47, ..., 92, 97. We need to count how many numbers are in the list 12, 17 ... 92, 97. To do this, let's add 3 to every term in the list to get 15, 20, ... 95, 100. Since the list is now full of multiples of 5 we can divide the list by 5 to get 3, 4, ... 19, 20 and then subtract 2 to get 1, 2, ... 17, 18 which means that there are 18 2-digit numbers.

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