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A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ball is also thrown at the same speed horizontally at the wall, but sticks to it upon hitting. [THE CLAY BALL / THE RUBBER BALL /NEITHER] (circle one) exerts a greater magnitude of impulse on the wall. Briefly explain (either in words or calculations)

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5 votes

Answer:

THE RUBBER BALL

Step-by-step explanation:

From the question we are told that

The mass of the rubber ball is
m_r = 2 \ kg

The initial speed of the rubber ball is
u = 3 \ m/s

The final speed at which it bounces bank
v - 3 \ m/s

The mass of the clay ball is
m_c = 2 \ kg

The initial speed of the clay ball is
u = 3 \ m/s

The final speed of the clay ball is
v = 0 \ m/s

Generally Impulse is mathematically represented as


I = \Delta p

where
\Delta p is the change in the linear momentum so


I = m(v-u)

For the rubber is


I_r = 2(-3 -3)


I_r = -12\ kg \cdot m/s

=>
|I_r| = 12\ kg \cdot m/s

For the clay ball


I_c = 2(0-3)


I_c = -6 \ kg\cdot \ m/s

=>
| I_c| = 6 \ kg\cdot \ m/s

So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball

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