Question

A body is thrown vertically upward and the height travelled by it is 200m , find the initial velocity and time required to reach maximum height ?

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Answer 1

Initial velocity(u)=62.6 m/s^2

Time(t)=6.39 seconds

Solution,

Displacement(s)=200 m

Initial velocity (u)=?

Final velocity(v)=0 m/s^2

acceleration due to gravity(g)=-9.8 m/s^2

now,

`{v}^(2) = {u}^(2) + 2as \\ {(0)}^(2) = {u}^(2) + 2 * ( - 9.8) * 200 \\ {u}^(2) = 2 * 9.8 * 200 \\ {u}^(2) = 3920 \\ u = √(3920) \\ u = \sqrt{ {62.6}^(2) } \\ u = 62.6 \: metre \: per \: second`

Again,

Finding time taken,

`v = u + at \\ t = (v - u)/(a) \\ = (0 - 62.6)/( - 9.8) \\ = ( - 62.6)/( - 9.8) \\ = 6.39 \: seconds`

Hope this helps...

Good luck on your assignment...