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Subtract: 6/2x^+8x - x/4x^+12x-16 = 6/2x(x+4) - x/4(x+4)(x-1) = 6•2(x-1)/2x(x+4)•2(x-1) - x•x/4(x+4)(x-1)•x

Subtract: 6/2x^+8x - x/4x^+12x-16 = 6/2x(x+4) - x/4(x+4)(x-1) = 6•2(x-1)/2x(x+4)•2(x-example-1
User Shadie
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1 Answer

7 votes

Answer:


$(-x^2+12x-12)/(4x(x+4)(x-1))$

Explanation:


$(6)/(2x(x+4))- (x)/(4(x+4)(x-1)) $


$(6\cdot2(x-1))/(2x(x+4)\cdot2(x-1))- (x\cdot x)/(4(x+4)(x-1)x) $


$(12(x-1))/(4x(x+4)(x-1))- (x^2)/(4x(x+4)(x-1)) $


$(12(x-1)-x^2)/(4x(x+4)(x-1))$


$(-x^2+12x-12)/(4x(x+4)(x-1))$

User Tusar
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