101k views
1 vote
A chemist is mixing a 50% salt solution with an 18% salt solution to make 40 L of a new solution that will contain 30% salt. How much of each of the original solutions should the chemist use?

User Selvakumar
by
8.8k points

1 Answer

10 votes

Answer:

See below

Explanation:

Sum of ingredients = sum of final solution

.50 x where x = 50 percent amount then 40 - x = 18% amount

.50 x + .18(40 - x) = .30 ( 40 )

.50 x + 7.2 - .18x = 12

.32x = 4.8

x = 15 L of 50% 25 liters of 18%

User Spectral
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories