Answer:
s= 8.28×10⁻¹⁶m
Step-by-step explanation:
given
V= 2.25×10³V
from conservation of energy
mv²/2=qΔV
v=√(2qΔV/m)
v= √(2×1.6×10⁻¹⁹×2.25×10³/9.1×10⁻³¹)
=√7.9×10¹⁴m/s
=2.8×10⁷m/s
the deflection of electron beam is
S= gt²/2
recall t= d/v
s=g(
)²/2
s=
×9.8×(0.364/2.8×10⁷)²
s= 8.28×10⁻¹⁶m