Because cylinder with a volume of 3.00dm^3 contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder? ( R=8.31)

Question

asked Apr 12, 2021 121k views

1 Answer

Surbhi Vyas · Answer 1 · 2021-04-17T17:29:55+0000

Answer:

Option A. 1110 KPa.

Step-by-step explanation:

The following data were obtained from the question:

Volume (V) = 3 dm³

Number of mole (n) = 8 moles

Temperature (T) = 50K

Gas constant (R) = 8.31 KPa.dm³/Kmol

Pressure (P) =..?

Pressure inside the cylinder can be obtained by using the ideal gas equation as follow:

PV =nRT

P x 3 = 8 x 8.31 x 50

Divide both side by 3

P= (8 x 8.31 x 50) /3

P = 1108 ≈ 1110 KPa

Therefore, the pressure inside the cylinder is 1110 KPa