Question

Badr cycled for 1.5 hours at an average speed of 18 km/h. Tabita travelled the same route as Badr but it took her 1 hour 15 minutes. What is Tabita's average speed to 1 dp?

Answer 1

21.6

Explanation:

Answer 2

Tabita's average speed was
`21.6\,\,(km)/(h)`

Explanation:

Let's start by finding the distance Badr covered during the 1.5 hour trip at the speed of 18 km/h. We use the velocity formula for that:

`vel=(distance)/(time) \\18=(distance)/(1.5) \\distance=18\,*\,1.5 \,\,km\\distance= 27\,\,km`

Using the same basic formula, we can now estimate Tabita's average speed knowing that it took her 1 hour and 15 minutes (1.25 hours) to complete the trip:

`vel=(distance)/(time) \\vel=(27\,\,km)/(1.25\,h)\\vel=21.6\,\,(km)/(h)`