Question

In Niels Bohr's 1913 model of the atom, the electron is in a circular orbit around a nucleus. An electron is 7.60 10-11 m from a nucleus traveling in a circular orbit with a speed of 2.45 106 m/s. (a) What is the magnitude of the magnetic moment due to the electron's motion?

Answer 1

14.896 x 10^-24

Step-by-step explanation:

• Mo = (evr)/2
• e = electron = 1.6 x 10^-19
• v = velocity
• r = radius =7.60 x 10^-11