Question

I NEED HELP PLEASE, THANKS! Light passes from air into water at an angle of 40.0° to the normal. What is the angle of refraction? Please show all work.

Answer 1

Angle of Refraction = 28.9 degrees

Step-by-step explanation:

We'll use Snell's law for this. It's mathematical form is:

=>
`n_1* sin(\alpha _1)=n_2 * sin(\alpha _2)`

Where
`n_(1) = 1, n_(2) = 1.33, \alpha _(2) = 40^o`

=>
`n_(1)` and
`n_(2)` are the refractive indexes of the air and water respectively.

Solution:

=> 1 * sin (40) = 1.33 * sin(
`\alpha _(2)`)

=> sin
`\alpha _(2)` =
`(sin 40^0)/(1.33)`

=> sin
`\alpha _(2)` = 0.4821

=>
`\alpha _(2)` = 28.9 degrees