Answer: Let t
be the time in seconds from the beginning of the motion of a particle. If the particle has a velocity of 4 m/s initially (at t=0
) and has a constant acceleration of 2 m/s2
, find the velocity of the particle:
when t=1
when t=2
after t
seconds.
Draw the velocity–time graph for the motion.
Solution
When t=1
, the velocity of the particle is 4+2=6
m/s.
When t=2
, the velocity of the particle is 4+2×2=8
m/s.
After t
seconds, the velocity of the particle is 4+2t
m/s.
Step-by-step explanation: