Question

A boy of mass 45kg sits 109cm to the left of the seesaw. Another boy of mass 29000g wants to balance the seesaw. At what distance he needs to sit?

Answer 1

166 cm

Step-by-step explanation:

Given :

d1 =109cm

M1= 45kg

M2=29000g = 29 kg

As we know that Newton second law

`Force\ =\ Mass\ *\ Acceleration`

Here M1= 45kg

and acceleration=
`9.81 m/s^(2)`

Therefore

`F1=45 * 9.81`

`F1= 441.45 N`

M2=29000g = 29 kg

Similarly

`F2= 29 * 9.81\\ F2= 284.4 N`

Now we using the Principal of moments

`F1 * d1 =F2 *d2`

`441.5 * 109\ =\ 290\ *\ d2\\48,123.5=290 d2\\d2 =165.9`

~ d2=166 cm