Question

What is the point-slope form of a line that has a slope of -4 and passes through point (-3, 1)?

Oy-(-3) --4(x-1)
O y-1--4[*-(-3)]
0 -1-y,--4-3-x;)
O 3-y,--4(1-x)

Answer 1

Option B)
`y - 1= -4 [x-(-3)]`

Explanation:

Slope = m = -4

Point = (x1,y1) = (-3,1)

So, x1 = -3, y1 = 1

Putting it in the point slope equation:

=>
`y-y1 = m(x-x1)`

=>
`y - 1= -4 [x-(-3)]`