Question

At a pressure of one atmosphere oxygen boils at −182.9°C and freezes at −218.3°C. Consider a temperature scale where the boiling point of oxygen is 100.0°O and the freezing point is 0°O. Determine the temperature on the Oxygen scale that corresponds to the absolute zero point on the Kelvin scale.

Answer 1

The temperature on the Oxygen scale that corresponds to absolute zero on the Kelvin scale is -100.0 °O.

Step-by-step explanation:

To determine the temperature on the Oxygen scale that corresponds to the absolute zero point on the Kelvin scale, we need to find the temperature difference between the boiling and freezing points of oxygen on the Oxygen scale. On the Kelvin scale, the temperature difference between the freezing and boiling points of water is 100 Kelvin. Since the temperature difference is the same on the Oxygen scale, we can calculate the temperature difference between the freezing and boiling points of oxygen on the Oxygen scale as 100.0 °O - 0 °O = 100.0 °O.

Now we can determine the temperature on the Oxygen scale that corresponds to absolute zero by subtracting the temperature difference on the Oxygen scale from the boiling point of oxygen on the Kelvin scale. Absolute zero on the Kelvin scale is 0 K, so the temperature on the Oxygen scale that corresponds to absolute zero is 0 - 100.0 °O = -100.0 °O.

Therefore, the temperature on the Oxygen scale that corresponds to absolute zero on the Kelvin scale is -100.0 °O.

Answer 2

Answer: -254.51°O

Step-by-step explanation:

Ok, in our scale, we have:

-182.9°C corresponds to 100° O

-218.3°C corresponds to 0°

Then we can find the slope of this relation as:

S = (100° - 0°)/(-182.9°C - (-218.3°C)) = 2.82°O/°C

So we can have the linear relationship between the scales is:

Y = (2.82°O/°C)*X + B

in this relation, X is the temperature in Celcius and Y is the temperature in the new scale.

And we know that when X = -182.9°C, we must have Y = 0°O

then:

0 = (2.82°O/°C)*(-182.9°C) + B

B = ( 2.82°O/°C*189.9°C) = 515.778°O.

now, we want to find the 0 K in this scale, and we know that:

0 K = -273.15°C

So we can use X = -273.15°C in our previous equation and get:

Y = (2.82°O/°C)*(-273.15°C) + 515.778°O = -254.51°O