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Suppose that IQ scores have a bell-shaped distribution with a mean of 103 and a standard deviation of 14. Using the empirical rule, what percentage of IQ scores are between 61 and 145

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Answer:


P(61<x<145)

And we can use the z score formula in order to find the deviationn above/below for the limits given given by:


z= (X -\mu)/(\sigma)

And replacing we got:


z=(61-103)/(14)= -3


z=(145-103)/(14)= 3

So then we want the % of values within 3 deviation from the mean and from the empirical rule we know that between these we have 99.7% of the data.

Explanation:

We know that the IQ scores have the following parameters:


\mu = 103, \sigma = 14

And we want to find the following probability:


P(61<x<145)

And we can use the z score formula in order to find the deviationn above/below for the limits given given by:


z= (X -\mu)/(\sigma)

And replacing we got:


z=(61-103)/(14)= -3


z=(145-103)/(14)= 3

So then we want the % of values within 3 deviation from the mean and from the empirical rule we know that between these we have 99.7% of the data.

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