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Calculate the electric potential due to a dipole whose dipole moment is 5.2×10−30 C⋅m at a point r = 2.8×10−9 m away. Suppose that r≫ℓ, where ℓ is the distance between the charges in the dipole.

User IronAces
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1 Answer

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Answer:

V = 8.01*10^-12 V

Step-by-step explanation:

In order to calculate the electric potential produced by the dipole you use the following formula:


V=k(p)/(r^2) (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

p: dipole moment = 5.2×10−30 C⋅m

r: distance to the dipole = 2.8*10^-9m

You replace the values of the parameters:


V=(8.98*10^9Nm^2/C^2)(5.2*10^(-30)Cm)/((2.8*10^(-9)m))\\\\V=8.01*10^(-12)V

The electric potential of the dipole is 8.01*10^-12V

User Bronumski
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