Answer:
CH4 ---> 2
CL2 ----> 4
HCL -----> 8
CO-------> 2
Step-by-step explanation:
Equation
CH4 + O2 + Cl2 => HCI + CO
we have to balance it
On LHS atoms of oxygen is 2 while on RHS it is 1 atom so lets balance oxygen first
to balance oxygen on RHS we add 2 as coefficient to CO
CH4 + O2 + Cl2 => HCI + 2CO
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On RHS atoms of Carbon is 2 while on RHS it is 1 atom so lets balance Carbon now
to balance Carbon on LHS we add 2 as coefficient to CH4
2CH4 + O2 + Cl2 => HCI + 2CO
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On LHS atoms of hydrogen is 8 so lets balance hydrogen now
to balance hydrogen on RHS we add 8 as coefficient to HCL
2CH4 + O2 + Cl2 => 8HCI + 2CO
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On RHS atoms of Cl is 8 while on LHS atoms of Cl is 2.
To make no of atoms of Cl 8 on LHS we add 4 as coefficient
2CH4 + O2 + 4Cl2 => 8HCI + 2CO
Thus, coefficients are as given below
CH4 ---> 2
CL2 ----> 4
HCL -----> 8
CO-------> 2