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Which substitution should be used to rewrite 16(x^3+1)^2-22(x^3+1)-3=0 as a equation?

User Kingname
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Answer:

The factorized form will be {(2x^3)-1}×{(8x^3)+9}=0

The simplified form will be (16x^6)+(10x^3)-9=0

User Pete Skelly
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