Question

What is the electric force acting between two charges of -0.0080 C and 0.0050

Answer 1

-2.9x10^8

Step-by-step explanation:

Answer 2

Step-by-step explanation:

It is required to find the electric force acting between two charges of -0.0080 C and 0.0050. Let the distance between them is r. So, the electrical force is given by :

`F=(kq_1q_2)/(r^2)`

So,

`F=(9* 9* 0.0080* 0.0050)/(r^2)\\\\F=(0.00324)/(r^2)`

Hence, this is the required solution.