Answer:
Explanation:
The 1208 km separation distance is closed in 4 hours, so the rate of closure is ...
(1208 km)/(4 h) = 302 km/h
If s represents the speed of the slower train, then the sum of their speeds is ...
s + (s+16) = 302
2s = 286
s = 143
s+16 = 159
The slower train's rate is 143 km/h; the faster train's is 159 km/h.