Question

Find the difference of functions s and r shown

below.
r(x) = -X2 + 3x
s(x) = 2x + 1
(s – r)(x) =

Answer 1

Answer & Step-by-step explanation:

In this problem, we are given two functions.

s(x) = 2x + 1

r(x) = -x² + 3x

We are asked to find the difference between s(x) and r(x).

(2x + 1) - (-x² + 3x)

Distribute the negative to the second parentheses.

2x + 1 + x² - 3x

Combine like terms and put the equation in standard form. This means the exponents should be in descending order.

x² - x + 1

So, (s - r)(x) equals x² - x + 1

Answer 2

(2x-1) - (-x^2 +3x)

THEN

x^2 - x + 1

Explanation:

Since youre subtracting r from s...

s(x) = 2x + 1

r(x) = -x^2 + 3x

you subtract the two to get an equation for the first step.

(s-r)(x) = (2x+1) - (-x^2 +3x)

for the next step, you're simplifying...

distribute the minus: (2x+1) + x^2 - 3x

combine like terms: x^2 + 1 - 1x

which gives you the answer of...

x^2 - x + 1

Hope this helps!!