1 Answer

Jeremiah Stillings · Answer 1 · 2021-10-14T01:26:36+0000

Answer:

answer B is correct

Explanation:

Hello,

this is not allowed to divide by 0 so we need to find the zeros of

x^2+2x-15=0

$<=> x^2-3x+5x-15=0\\<=> x(x-3)+5(x-3)=0\\<=> (x+5)(x-3)=0\\<==> x=-5 \ \ or \ \ x=3$

we need x different from -5 and from 3

answer B is correct

hope this helps

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