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Someone please help me with question 3.b) ​

Someone please help me with question 3.b) ​-example-1
User Tdurnford
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1 Answer

5 votes

Answer:

  • AM = 12.87 cm
  • CM = 8.578 cm
  • OD = 23.66 cm

Explanation:

Since the figure is symmetrical, angle MOA will be half of angle BOA, so will be 130°/2 = 65°. The tangent ratio is useful here. It tells you ...

tan(MOA) = MA/OA

AM = OA·tan(MOA) = 6·tan(65°)

AM ≈ 12.87 . . . cm

__

Similarly, ...

CM = 4·tan(65°)

CM ≈ 8.578 . . . cm

__

The cosine ratio is useful for finding OD.

cos(MOA) = OA/OM

OM = OA/cos(MOA) = 6/cos(65°)

Similarly, ...

DM = 4/cos(65°)

The length we want is OD, so ...

OD = OM +DM = 6/cos(65°) +4/cos(65°) = 10/cos(65°)

OD ≈ 23.66 . . . cm

Someone please help me with question 3.b) ​-example-1
User Tyler Crompton
by
8.5k points

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