Question

Solve the following system of equations. What is one x-value of a solution?

f(x) = x2 + 4x + 10 g(x) = -32x - 40

a. x = 5

b. x = -5

c. x = 6

d. x = 2

Answer 1

its b

Explanation:

I did it

Answer 2

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

`x = (-b \pm √(b^2-4(a)(c)))/(2(a))`

`x = (-36 \pm √(36^2-4(1)(50)))/(2(1))`

`x = (-36 \pm 33.11)/(2)`

`x_1 = (-36 + 33.11)/(2)`

`x_1 = -1.445`

`x_2 = (-36 - 33.11)/(2)`

`x_2 = -34.555`