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A 25 gram sample of a substance that's used for drug research has a k-value of 0.1205. Find the substance's half life in days, round to the nearest tenth.

User Tamicka
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Situation: A 25 gram sample of a substance used for drug research has a k-value of 0.1205.
N=N_0e^-kt


  • N_0= initial mass(at time t=0)
  • N= mass at a time t
  • K= a positive constant that depends on the substance itself and on the units used to measure time
  • T=time, in days

Find the substance's half-life in days, round to the nearest tenth.

Answer:

5.8 days

Explanation:

The decay model for drugs and radioactive substances is given as


N=N_0e^(-Kt)

The half-life of any substance is the time it takes for the substance to decay to half its initial amount. That is the period it takes for:


N(t)=(N_0)/(2)

If we substitute this into the model, we obtain:


(N_0)/(2)=N_0e^(-Kt)\\$Dividing both sides by N_o\\\frac12=e^(-Kt)

We can solve for t.

Taking the natural logarithm of both sides


\ln\frac12=\ln e^(-Kt)\\\implies-\ln2=-Kt\\t=(\ln2)/(k) \\$Since k=0.1205$\\t_(1/2)=(\ln2)/(0.1205)=5.8$ days (to the nearest tenth)

User Gabriel Staples
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