Question

A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electric field of magnitude 95.0 N/C that is directed at 20∘ from the plane of the sheet.

Required:
Find the magnitude of the electric flux through the sheet.

Answer 1

ФE = 9.403W

Step-by-step explanation:

In order to calculate the magnitude of the electric flux trough the sheet, you use the following formula:

`\Phi_E=\vec{A}\cdot \vec{E}=AEcos\theta` (1)

A: area of the rectangular sheet = (0.400m)(0.600m) = 0.24m^2

E: magnitude of the electric field = 95.0N/C

θ: angle between the direction of the electric field and the normal to the surface of the sheet

You replace the values of the parameters in the equation (1):

`\Phi_E=(0.24m^2)(95.0N/m)cos(20\°)=9.304W`

The magnitude of the electric flux is trough the sheet is 9.403W