Answer:
B. Rate = k[A]
order of reaction = 1
k = 0.213 s-1
Step-by-step explanation:
Hello,
In this case, you should consider the experiments and how the concentration of both A and B affect the rate, thus, we can make some conclusions:
- Between the experiment 1 and 2, we can notice that modifying the concentration of B does not affect the rate as it remains in 3.20 x 10-1 M/s, for that reason the reaction is zeroth-order respect to B.
- Between the experiment 2 and 3, we can notice that doubling the concentration of A from 1.50 M to 3.00 M results in a doubling of the rate from 3.20 x 10-1 M/s to 6.40 x 10-1 M/s, for that reason, we can infer that the reaction is first-order respect to A.
In such a way, we can infer that the rate law is:
![Rate=k[A]^1[B]^0\\\\Rate= k[A]](https://img.qammunity.org/2021/formulas/chemistry/college/34rxl8i2ek8xzhh2999q2kj33ohu6tqpsv.png)
Thus, the order of reaction is first-order and the rate constant turns out:
![k=(Rate)/([A])=(3.2x10^(-1)M/s)/(1.50M)\\ \\k=0.213s^(-1)](https://img.qammunity.org/2021/formulas/chemistry/college/ioe6537qtpz769ul0ix9xnf4q37lgo1l81.png)
Therefore, answer is:
B. Rate = k[A]
order of reaction = 1
k = 0.213 s-1
Regards.