Answer:
y = -1/2x + 2
Explanation:
If two lines are perpendicular then the product of their slopes are -1
m1*m2 = -1
where m1 amd m2 is slope of two lines.
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Given line
y = 2x-3\
it is in form of y = mx+c (slope intercept form)
where m is slope and c is y intercept
Thus, slope of line y = 2x-3 is 2
Now we know that product of two lines are -1
let m be slope of other line
then m*2 = -1
m = -1/2
thus, slope of required line is -1/2
let the line be y = mx+c but m = -1/2
thus
y = -1/2 x + c
given that point(-6,5) lies on it
we use -6 in plca of x and 5 in place of y
5 = -1/2 *-6 + c
=>5 = 3 +c
=> c = 5-3 = 2
Thus, equation that is perpendicular to the line y=2x-3 and passes through the point (-6,5) is y = -1/2x + 2