Question

Hi, I'm often really slow at learning math and my condition makes it harder, can someone help me?

Find the zeroes of the function and state their multiplicities.
q(x) = 10x^3 - 58x^2 + 40x

Answer 1

The answer: 0, 4/5 and 5


Explanation: first, we factor out 2x and get: 2x(5x^2-29x+20)=0

In order for this equation to be equal to zero, either 2x must equal to zero or (5x^2-29x+20) must equal to zero

Having said that, if:
2x = 0
X=0

If:
(5x^2-29x+20) = 0
X=4/6, x=5