Answer:
Money invested in Canada saving bond is $6000.
Money invested in provincial government bond is $9000.
Explanation:
First of all, let us have a look at the formula for simple interest:
![SI = (P* R* T)/(100)](https://img.qammunity.org/2021/formulas/mathematics/high-school/uoh1ey208mmjjilzh4i8qtc3ckrz8cedkv.png)
Where P is the amount invested
R is the rate of interest and
T is the time
We are given here, 2 bonds in which a total of $15000 were invested
Let money invested in Canada saving bond
, = $x
Rate of interest,
![R_1=4\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/mowj36mea93h1qtuim3l5wonf96ugg9smy.png)
Time,
![T_1 = 1\ year](https://img.qammunity.org/2021/formulas/mathematics/high-school/bvo7ds5igkjgc0vf7kj9k2fpqt8jsq3qag.png)
![SI_1 = (P_1* R_1* T_1)/(100)\\\Rightarrow (x* 4* 1)/(100) ..... (1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/fog4w7jb0xkms1mxwrp43ib05qb9ydmtwv.png)
Let money invested in provincial government bond
, = $(15000-x)
Rate of interest,
![R_2=5\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/s8apk0v1l8ob9ht9qjx10yhnishtbnqdkl.png)
Time,
![T_2 = 1\ year](https://img.qammunity.org/2021/formulas/mathematics/high-school/shiu9eam0145l5i7r7ot5ikbfdjaoqles7.png)
![SI_2 = (P_2* R_2* T_2)/(100)\\\Rightarrow ((15000-x)* 5* 1)/(100) ..... (2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gl1m7i6dsr9ad1blphurv7lhzpprnwajyh.png)
We are given that
![SI_1+SI_2=$690\\\text{Using equations (1) and (2):}\\\\\Rightarrow (4x)/(100) + ((15000-x)* 5)/(100) = 690\\\Rightarrow 4x + (75000-5x) = 69000\\\Rightarrow x = \$6000](https://img.qammunity.org/2021/formulas/mathematics/high-school/tcw866tgwv6gkw0znxtqkkcs5656uis4lc.png)
Money invested in Canada saving bond = $6000
Money invested in provincial government bond = $15000-$6000 = $9000