Question

What is the mole fraction of a acetyl bromide

Answer 1

Mole fraction(CHCl3) = 0.681

Mole fraction (CH3COBr) = 0.319

Step-by-step explanation:

Molar mass(CHCl3) = 12+ 1 + 3*35.5 = 119.5 g/mol

Molar mass(CH3COBr) = 2*12 + 3*1 + 16 + 80 = 123 g/mol

112. g* 1mol/119.5g = 0.9372 mol CHCl3

54. g * 1 mol/123g = 0.4390 mol CH3COBr

Mole fraction(CHCl3) = 0.9372/(0.9372+0.4390) = 0.681

Mole fraction (CH3COBr) = 0.4390/(0.9372+0.4390) = 0.319

0.681+0.319 =1.000 true