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On a coordinate plane, 2 exponential functions are shown. Function f (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-axis at (0, 0.5) and goes through (1, 4). Function g (x) approaches y = 0 in quadrant 3 and decreases into quadrant 4. It crosses the y-axis at (0, negative 0.5) and goes through (1, negative 4).

Which function represents g(x), a reflection of f(x) = Two-fifths (10)x across the x-axis?

g(x) = Negative two-fifths(10)x
g(x) = Negative two-fifths (one-tenth) Superscript x
g(x) = Two-fifths (one-tenth) Superscript negative x
g(x) = Two-fifths(10)-x

User Bek
by
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2 Answers

4 votes

Answer:

answer is A

Explanation:

User Timothy Baldwin
by
6.6k points
7 votes

Answer:

g(x) = Negative two-fifths(10)x

Explanation:

In order to reflect a function over the x-axis, you have to multiply the function by minus one.

Given the function:

f(x) = 2/5(10)^x

Its reflection over the x-axis is:

-f(x) = -2/5(10)^x = g(x)

User Dheeraj Agrawal
by
6.9k points
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