Question

NEED MATH HELP NOW!!!PLEASE HELP!!!

Answer 1

Explanation:

The given equation of a parabola is,

`y=-(1)/(2)(x+3)^2+4`

When we compare this equation with the vertex form of the quadratic equation,

y = a(x - h)² + k

where (h, k) is the vertex,

Vertex of the parabola,

(-3, 4)

y-intercept,

`y=-(1)/(2)(0+3)^2+4`

`y=-(9)/(2)+4`

`y=-(1)/(2)`

x-intercepts,

`0=-(1)/(2)(x+3)^2+4`

`(1)/(2)(x+3)^2=4`

(x + 3) = ±√8

x = (3 - 2√2), (3 + 2√2)

Axis of symmetry,

x = -3

Domain:

(-∞, ∞)

Range:

(-∞, 4]