How many particles are in 0.645g of CaCl2

asked May 19, 2023 6.4k views

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8 votes

Answer:

~ 3.5 x 10^21

Step-by-step explanation:

Mole weight of Ca Cl2 ( from periodic table ) = ~~ 111 gm

.645 gm / 111 gm / mole X 6.022 x 10^23 =

OnklMaps answered May 24, 2023

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